Report Issue

JEE MAIN 2019
9-1-19 S2
Question
A 15 g mass of nitrogen gas is enclosed in a vessel at a temperature $27^{\circ} \mathrm{C}$. Amount of heat transferred to the gas, so that rms velocity of molecules is doubled, is about: [Take $\mathrm{R}=83 \mathrm{~J} / \mathrm{K}$ mole]
Select the correct option:
A
3 kJ
B
14 kJ
C
10 kJ
D
0.9 kJ
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\begin{aligned} & \frac{V_1}{V_2}=\sqrt{\frac{T_1}{T_2}} \\ & T_2=1200 \mathrm{~K} \\ & Q=n C_V\left(T_2-T_1\right) \\ & =\frac{15}{28} \times 5 \times \frac{R}{2} \times 900=10\end{aligned}$
Question Tags
JEE Main
Physics
Medium
Start Preparing for JEE with Competishun