A block is sliding down on an inclined... | Laws of Motion

JEE MAIN 2026

23-01-26 S2

Question

A block is sliding down on an inclined plane of slope $\theta$ and at an instant $t=0$ this block is given an upward momentum so that it starts moving up on the inclined surface with velocity $u$. The distance ( $S$ ) travelled by the block before its velocity become zero, is $\_\_\_\_$ . ( $\mathrm{g}=$ gravitational acceleration)

Select the correct option:

$\frac{u^2}{4 g \sin \theta}$

$\frac{2 u^2}{g \cos \theta}$

$\frac{u^2}{\sqrt{2} g \cos \theta}$

$\frac{u^2}{2 g \cos \theta}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution