$\begin{aligned} & P\left(T_{1 \mathrm{w}}\right)=\frac{1}{2}, P\left(T_{1 \mathrm{D}}\right)=\frac{1}{6}, P\left(T_{1 \mathrm{~L}}\right)=\frac{1}{3} \\ & 3 \\ & x>y \Rightarrow \frac{1 \mid 2}{T_1} \\ & P(W, W D)=\frac{1}{2} \times\left(\frac{1}{2}+\frac{1}{6}\right)\end{aligned}$
$\begin{aligned} & =\frac{1}{2} \times\left(\frac{6+2}{12}\right) \\ & =\frac{8}{24}=\frac{1}{3} \\ & P(D \text { and } W)=\frac{1}{6} \times \frac{1}{2}=\frac{1}{12} \\ & \Rightarrow P(x>y)=\frac{1}{3}+\frac{1}{12}=\frac{4}{12}+\frac{1}{12}=\frac{5}{12} \Rightarrow \mathbf{B}\end{aligned}$