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JEE MAIN 2019
08-04-2019 S2
Question
A body of mass $m_1$ moving with an unknown velocity of $v_1 \hat{i}$, undergoes a collinear collision with a body of mass $\mathrm{m}_2$ moving with a velocity $\mathrm{v}_2 \hat{\mathrm{i}}$. After collision, $\mathrm{m}_1$ and $\mathrm{m}_2$ move with velocities of $\mathrm{v}_3 \hat{\mathrm{i}}$ and $\mathrm{v}_4 \hat{\mathrm{i}}$, respectively. If $\mathrm{m}_2 =0.5 \mathrm{~m}_1$ and $\mathrm{v}_3=0.5 \mathrm{v}_1$, then $\mathrm{v}_1$ is :
Select the correct option:
A
$v_4=\frac{v_2}{4}$
B
$V_4-V_2$
C
$V_4+V_2$
D
$v_4=\frac{v_2}{2}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\begin{aligned} & m_1 v_1+m_2 v_2=m_1 v_3+m_2 v_4 \\ & m_1 v_1+0.5 m_1 v_2=0.5 m_1 v_1+0.5 m_1 v_4 \\ & v_1=v_4-v_2\end{aligned}$
Question Tags
JEE Main
Physics
Medium
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