A car accelerates from rest|RECTILINEAR MOTION|JEEMAIN 2021

_JEE_MAIN_2021

170321

Question

A car accelerates from rest at a constant rate $\alpha$ for some time after which it decelerates at a constant rate $\beta$ to come to rest. If the total time elapsed is t seconds, the total distance travelled is:

Select the correct option:

$\frac{4 \alpha \beta}{(\alpha+\beta)} t^2$

$\frac{2 \alpha \beta}{(\alpha+\beta)} t^2$

$\frac{\alpha \beta}{2(\alpha+\beta)} t^2$

$\frac{\alpha \beta}{4(\alpha+\beta)} t^2$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Easy

Start Preparing for JEE with Competishun

Report Issue