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JEE MAIN 2023
11-4-2023
Question
A metallic cube of side 15 cm moving along y-axis at a uniform velocity of $2 \mathrm{~ms}^{-1}$. In a region of uniform magnetic field of magnitude 0.5 T directed along z -axis. In equilibrium the potential difference between the faces of higher and lower potential developed because of the motion through the field will be $\_\_\_\_$.
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Solution
Sol. $$ \begin{aligned} & \Delta V=(v \times B) d \\ & \Delta V=(2 \times 1 / 2) 0.15 \\ & \Delta V=150 \mathrm{mV} \end{aligned} $$
Question Tags
JEE Main
Chemistry
Hard
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