A microwave of wavelength 2.0cm falls normally on a slit of width 4.0 cm. The angular spread of the central maxima of the diffraction pattern obtained on a screen 1.5m away from the slit, will be:
Select the correct option:
A
$ 30^{\circ} $
B
$15^{\circ}$
C
$60^{\circ}$
D
$45^{\circ}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
For first minima a $\sin \theta=\lambda$
$$
\begin{aligned}
& \sin \theta=\frac{\lambda}{\mathrm{a}}=\frac{1}{2} \\
& \theta=30^{\circ}
\end{aligned}
$$
Angular spread $=60^{\circ}$
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