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JEE MAIN 2024
01-02-2024 S2
Question
A particle initially at rest starts moving from reference point. x=0 along x-axis, with velocity v that varies as v=$4 \sqrt{\mathrm{x}} \mathrm{m} / \mathrm{s}$. The acceleration of the particle is $\mathrm{ms}^{-2}$ .
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Question Tags
JEE Main
Physics
Easy
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