A projectile is projected with velocity of 25... | Projectile Motion

JEE MAIN 2022

24-06-22 S1

Question

A projectile is projected with velocity of 25 m/s at an angle $\theta$ with the horizontal. After t seconds its inclination with horizontal becomes zero. If R represents horizontal range of the projectile, the value of $\theta$ will be : [use $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$ ]

Select the correct option:

$\frac{1}{2} \sin ^{-1}\left(\frac{5 t^2}{4 R}\right)$

$\frac{1}{2} \sin ^{-1}\left(\frac{4 \mathrm{R}}{5 \mathrm{t}^2}\right)$

$\tan ^{-1}\left(\frac{4 t^2}{5 R}\right)$

$\cot ^{-1}\left(\frac{\mathrm{R}}{20 \mathrm{t}^2}\right)$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution