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JEE MAIN 2021
20-07-21 S2
Question
A radioactive substance decays to $\left(\frac{1}{16}\right)^{\text {th }}$ of its initial activity in 80 days. The half life of the radioactive substance expressed in days is $\_\_\_\_$ .
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Solution
N₀ ──t₁⁄₂──> N₀/2 ──t₁⁄₂──> N₀/4 ──t₁⁄₂──> N₀/8 ──t₁⁄₂──> N₀/16 4 × t₁⁄₂ = 80 t₁⁄₂ = 20 days
Question Tags
JEE Main
Physics
Easy
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