A ring and a solid sphere..... | JEE Main 2024 | Rotational

JEE MAIN 2024

27-01-24 S2

Question

A ring and a solid sphere roll down the same inclined plane without slipping. They start from rest. The radii of both bodies are identical and the ratio of their kinetic energies is $\frac{7}{x}$ where x is

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Solution

In pure rolling work done by friction is zero. Hence potential energy is converted into kinetic energy. Since initially the ring and the sphere have same potential energy, finally they will have same kinetic energy too.
∴ Ratio of kinetic energies = 1
$\Rightarrow \frac{7}{x}=1 \Rightarrow x=7$

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