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JEE MAIN 2019
11-01-2019 S2
Question
A simple pendulum of length 1 m is oscillating with an angular frequency $10 \mathrm{rad} / \mathrm{s}$. The support of the pendulum starts oscillating up and down with a small angular frequency of $1 \mathrm{rad} / \mathrm{s}$ and an amplitude of $10^{-2} \mathrm{~m}$. The relative change in the angular frequency of the pendulum is best given by
Select the correct option:
A
$10^{-3} \mathrm{rad} / \mathrm{s}$
B
$10^{-1} \mathrm{rad} / \mathrm{s}$
C
$10^{-5} \mathrm{rad} / \mathrm{s}$
D
$1 \mathrm{rad} / \mathrm{s}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
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