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JEE MAIN 2023
06-04-23 S2
Question
A small particle of mass $m$ moves in such a way that its potential energy $U=\frac{1}{2} m \omega^2 r^2$ where $\omega$ is constant and $r$ is the distance of the particle from origin. Assuming Bohr's quantization of momentum and circular orbit, the radius of nth orbit will be proportional to.
Select the correct option:
A
$\sqrt{n}$
B
n
C
$\mathrm{n}^2$
D
$\frac{1}{n}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Physics
Hard
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