Electrochemistry | JEE Main 2025 Solution

JEE MAIN 2025

22-01-2025 SHIFT-1

Question

A solution of aluminium chloride is electrolysed for 30 minutes using a current of 2 A . The amount of the aluminium deposited at the cathode is $\_\_\_\_$.
[Given : molar mass of aluminium and chlorine are $27 \mathrm{~g} \mathrm{~mol}^{-1}$ and $35.5 \mathrm{~g} \mathrm{~mol}^{-1}$ respectively. Faraday constant $\left.=96500 \mathrm{Cmol}^{-1}\right]$

Select the correct option:

0.336 b

1.007 g

0.441 g

1.660 g

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

gm equivalent of Al deposited =$\frac{\mathrm{It}}{96500}$
$\frac{\mathrm{w}}{27} \times 3=\frac{2 \times 30 \times 60}{96500}$ ; $\mathrm{w}=0.336 \mathrm{~g}$

Question Tags

JEE Main

Chemistry

Easy

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