A wire of length L is hanging from a fixed... | Elasticity and Viscosity

JEE MAIN 2022

{S1}_29.06.22

Question

A wire of length $L$ is hanging from a fixed support. The length changes to $L_1$ and $L_2$ when masses 1 kg and 2 kg are suspended respectively from its free end. Then the value of $L$ is equal to :

Select the correct option:

$\sqrt{L_1 L_2}$

$\frac{\mathrm{L}_1+\mathrm{L}_2}{2}$

$2 \mathrm{~L}_1-\mathrm{L}_2$

$3 \mathrm{~L}_1-2 \mathrm{~L}_2$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Easy

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