All resistances in figure |Current Electricity|JEE-MAIN 2022

JEE MAIN 2022

28-06-22 S2

Question

" All resistances in figure are "1Omega" each. The value of current ' "l" ' is "(a)/(5)A". The value of "a" is "

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Solution

\begin{aligned} R_{eq} = \frac{15 R}{8} = \frac{15}{8} Ω \\ I = \frac{3}{\frac{15}{8}} = \frac{8}{5} A ∴ a = 8 \end{aligned}

Question Tags

JEE Main

Physics

Hard

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