Particle and a proton accelerated|ElectrostaticsJEEMain2022

JEE MAIN 2022

29-07-2022 S2

Question

An $\alpha$ particle and a proton are accelerated from rest through the same potential difference. The ratio of linear momenta acquired by above two particals will be :

Select the correct option:

$\sqrt{2}: 1$

$2 \sqrt{2}: 1$

$4 \sqrt{2}: 1$

$8: 1$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

$\begin{aligned} & \mathrm{p}=\sqrt{2 \mathrm{mE}}=\sqrt{2 \mathrm{mqV}} \\ & \frac{\mathrm{p}_\alpha}{\mathrm{p}_{\mathrm{p}}}=\sqrt{\frac{\mathrm{m}_\alpha \mathrm{q}_\alpha}{\mathrm{m}_{\mathrm{p}} \mathrm{q}_{\mathrm{p}}}}==\sqrt{\frac{4}{1} \times \frac{2}{1}}=\frac{2 \sqrt{2}}{1}\end{aligned}$

Question Tags

JEE Main

Physics

Easy

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