Electric field energy | Electrostatics

JEE MAIN 2019

11-01-2019 S2

Question

An electric field of $1000 \mathrm{~V} / \mathrm{m}$ is applied to an electric dipole at angle of $45^{\circ}$. The value of electric dipole moment is $10-29 \mathrm{Cm}$. What is the potential energy of the electric dipole?

Select the correct option:

$-9 \times 10^{-20} \mathrm{~J}$

$-10 \times 10^{-29} \mathrm{~J}$

$-7 \times 103^{-27} \mathrm{~J}$

$-20 \times 310^{-18} \mathrm{~J}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Easy

Start Preparing for JEE with Competishun

Report Issue