Periodic Table JEE Main Solution | Ionic Character Order

JEE MAIN 2025

29-01-2025 SHIFT-1

Question

An element 'E' has the ionisation enthalpy value of $374\;{\rm{kJ}}\;{\rm{mo}}{{\rm{l}}^{ - 1}}$. 'E' reacts with elements A, B, C and D with electron gain enthalpy values of $ - 328, - 349, - 325$ and $ - 295\;{\rm{kJ}}\;{\rm{mo}}{{\rm{l}}^{ - 1}}$, respectively. The correct order of the products EA, EB, EC and ED in terms of ionic character is :

Select the correct option:

${\rm{ED}} > {\rm{EC}} > {\rm{EB}} > {\rm{EA}}$

${\rm{EA}} > {\rm{EB}} > {\rm{EC}} > {\rm{ED}}$

${\rm{ED}} > {\rm{EC}} > {\rm{EA}} > {\rm{EB}}$

${\rm{EB}} > {\rm{EA}} > {\rm{EC}} > {\rm{ED}}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Difference between I.E. & E.G.E increases, ionic character increases.

Question Tags

JEE Main

Chemistry