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JEE Advance 2013
Paper-1
Multiple correct answers - Select all that apply
Question
A horizontal stretched string, fixed at two ends, is vibrating in its fifth harmonic according to the equation, $y(x$, $\mathrm{t})=(0.01 \mathrm{~m}) \sin \left[\left(62.8 \mathrm{~m}^{-1}\right) \mathrm{x}\right] \cos \left[\left(628 \mathrm{~s}^{-1}\right) \mathrm{t}\right]$. Assuming $\pi=3.14$, the correct statement $(\mathrm{s})$ is (are) :
Select ALL correct options:
A
The number of nodes is 5 .
B
The length of the string is 0.25 m .
C
The maximum displacement of the midpoint of the string its equilibrium position is 0.01 m .
D
The fundamental frequency is 100 Hz .
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
⚠ Partially correct. Some answers are missing.
Solution
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JEE Advance
Physics
Easy
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