Thermodynamics | JEE Main 2025 Solution

JEE MAIN 2025

28-01-2025 SHIFT-2

Question

An ideal gas undergoes a cyclic transformation starting from the point $A$ and coming back to the same point by tracing the path $\mathrm{A} \rightarrow \mathrm{B} \rightarrow \mathrm{C} \rightarrow \mathrm{D} \rightarrow \mathrm{A}$ as shown in the three cases above. Choose the correct option regarding $\Delta \mathrm{U}$ :

Select the correct option:

$\Delta \mathrm{U}($ Case-I $)>\Delta \mathrm{U}($ Case-II $)>\Delta \mathrm{U}($ Case-III $)$

$\Delta \mathrm{U}($ Case-I $)>\Delta \mathrm{U}($ Case-III $)>\Delta \mathrm{U}($ Case-II $)$

$\Delta \mathrm{U}($ Case-I $)=\Delta \mathrm{U}($ Case-II $)=\Delta \mathrm{U}($ Case-III $)$

$\Delta \mathrm{U}($ Case-III $)>\Delta \mathrm{U}($ Case-II $)>\Delta \mathrm{U}($ Case-I $)$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

As internal energy ' $U$ ' is a state function, its cyclic integral must be zero in a cyclic process
$\therefore \Delta$ U case (I) $=\Delta$ U case (II) $=\Delta$ U case (III)

Question Tags

JEE Main

Chemistry

Medium

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