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JEE MAIN 2020
08-01-20 S2
Question
As shown in fig. when a spherical cavity (centred at O) of radius 1 is cut out of a uniform sphere of radius R (centred at C), the centre of mass of remaining (shaded) part of sphere is at G, i.e. on the surface of the cavity. R can be determined by the equation
Select the correct option:
A
(1) $\left(R^2+R+1\right)(2-R)=1$
B
$\left(R^2-R+1\right)(2-R)=1$
C
$\left(R^2-R-1\right)(2-R)=1$
D
$\left(R^2+R-1\right)(2-R)=1$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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