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JEE Advance 2008
Paper-2
Question
Consider a branch of the hyperbola $x^2-2 y^2-2 \sqrt{2} x-4 \sqrt{2} y-6=0$ with vertex at the point $A$. Let $B$ be one of the end points of its latus rectum. If $C$ is the focus of the hyperbola nearest to the point $A$, then the area of the triangle $A B C$ is
Select the correct option:
A
$1-\sqrt{\frac{2}{3}}$
B
$\sqrt{\frac{3}{2}}-1$
C
$1+\sqrt{\frac{2}{3}}$
D
$\sqrt{\frac{3}{2}}+1$
✓ Correct! Well done.
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Solution
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JEE Advance
Mathematics
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