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JEE MAIN 2021
25-07-2021 S2
Question
Consider the function $$ \begin{array}{ll} f(x)=\frac{P(x)}{\sin (x-2)}, & x \neq 2 \\ =7 & x=2 \end{array} $$ Where $\mathrm{P}(\mathrm{x})$ is a polynomial such that $\mathrm{P}^{\prime \prime}(\mathrm{x})$ is always a constant and $\mathrm{P}(3)=9$. If $\mathrm{f}(\mathrm{x})$ is continuous at $\mathrm{x}=2$, then $\mathrm{P}(5)$ is equal to $\_\_\_\_$ .
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Question Tags
JEE Main
Mathematics
Medium
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