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JEE Advance 2008
Paper-2
Question
Consider the lines $$ \begin{aligned} & L_1: \frac{x+1}{3}=\frac{y+2}{1}=\frac{z+1}{2} \\ & L_2: \frac{x-2}{1}=\frac{y+2}{2}=\frac{z-3}{3} \end{aligned} $$
The shortest distance between $\mathrm{L}_1$ and $\mathrm{L}_2$ is
Select the correct option:
A
0.0
B
$\frac{17}{\sqrt{3}}$
C
$\frac{41}{5 \sqrt{3}}$
D
$\frac{17}{5 \sqrt{3}}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Mathematics
Easy
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