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JEE MAIN 2025
22-01-2025 SHIFT-2
Question
Density of 3 M NaCl solution is 1.25 g/mL. The molality of the solution is :
Select the correct option:
A
1.79 m
B
3 m
C
2.79 m
D
2 m
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\begin{aligned} & 3 \mathrm{MNaCl}, \mathrm{d}_{\mathrm{sol}}=1.25 \mathrm{gm} / \mathrm{mol} \\ & \text { Molality }=\frac{\mathrm{M} \times 1000}{1000 \mathrm{~d}-\mathrm{M} \times \mathrm{M}_{\mathrm{w}}}=\frac{3000}{1250-175.5}=2.79\end{aligned}$
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