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JEE MAIN 2023
31-01-23 S1
Question
Expression for an electric field is given by $\overrightarrow{\mathrm{E}}=4000 \mathrm{x}^2 \hat{\mathrm{i}} \frac{\mathrm{V}}{\mathrm{m}}$. The electric flux through the cube of side 20 cm when placed in electric field (as shown in the figure) is $\_\_\_\_$ V cm.
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