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JEE MAIN 2020
04.09.20_S2
Question
Find the binding energy per nucleon for ${ }_{50}^{120} \mathrm{Sn}$. Mass of proton $m_p=1.00783 \mathrm{U}$, mass of neutron $m_n=1.00867 \mathrm{U}$ and mass of tin nucleus $m_{S n}=119.902199 \mathrm{U}$. (take $1 \mathrm{U}=$
Select the correct option:
A
9.0 MeV
B
8.5 MeV
C
8.0 MeV
D
7.5 MeV
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Solution
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Question Tags
JEE Main
Physics
Easy
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