Following figure show | KTG & THERMODYNAMICS

JEE MAIN 2019

09-04-2019 - S1

Question

Following figure shows two processes A and B for a gas. If $\Delta Q_A$ and $\Delta Q_B$ are the amount of heat absorbed by the system in two cases, and $\Delta \mathrm{U}_{\mathrm{A}}$ and $\Delta \mathrm{U}_{\mathrm{B}}$ are changes in internal energies, respectively, then:

Select the correct option:

$\Delta Q_A>\Delta Q_B, \Delta U_A=\Delta U B$

$\Delta Q_A=\Delta Q_B ; \Delta U_A=\Delta U B$

$\Delta Q_A>\Delta Q_B, \Delta U_A>\Delta U B$

$\Delta Q_A<\Delta Q_B, \Delta U_A<\Delta U B$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution