Report Issue

JEE MAIN 2024
1-2-2024 S2
Question
For a certain reaction at $300 \mathrm{~K}, \mathrm{~K}=10$, then $\Delta \mathrm{G}^{\circ}$ for the same reaction is $\times 10^{-1} \mathrm{~kJ} \mathrm{~mol}^{-1}$. (Given $\left.\mathrm{R}=8.314 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\right)$ ]
Write Your Answer
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Chemistry
Easy
Start Preparing for JEE with Competishun