For the reaction
$2 \mathrm{Fe}^{3+}(\mathrm{aq})+2 \mathrm{I}^{-}(\mathrm{aq}) \rightarrow 2 \mathrm{Fe}^{2+}(\mathrm{aq})+\mathrm{I}_2(\mathrm{~s})$ the magnitude of the standard molar free energy change, $\Delta_{\mathrm{r}} \mathrm{G}_{\mathrm{m}}^0=-$ $\_\_\_\_$ kJ (Round off to the Nearest Integer).
$\left[\begin{array}{ll}E_{\mathrm{Fe}^{2+} / \mathrm{Fe}(\mathrm{s})}=-0.440 \mathrm{~V} ; & E_{\mathrm{Fe}^{3+} / \mathrm{Fe}(\mathrm{s})}^0=-0.036 \mathrm{~V} \\ E_{\mathrm{I}_2 / 2 \mathrm{I}^{-}}^0=0.539 \mathrm{~V} ; & \mathrm{F}=96500 \mathrm{C}\end{array}\right]$