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JEE MAIN 2021
18-03-21 S1
Question
What will be the average value of energy along one degree of freedom for an ideal gas in thermal equilibrium at a temperature T ? ( $\mathrm{k}_{\mathrm{B}}$ is Boltzmann constant)
Select the correct option:
A
$\frac{1}{2} \mathrm{k}_{\mathrm{a}} \mathrm{T}$
B
$\frac{2}{3} \mathrm{k}_{\mathrm{a}} \mathrm{T}$
C
$\frac{3}{2} \mathrm{k}_{\mathrm{a}} \mathrm{T}$
D
$\mathrm{K}_{\mathrm{a}} \mathrm{T}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Energy associated with each degree of freedom per molecule $=\frac{1}{2} k_a T$.
Question Tags
JEE Main
Physics
Easy
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