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JEE MAIN 2025
24-01-2025 SHIFT-2
Question
If $\alpha>\beta>\gamma>0$, then the expression $\cot ^{-1}\left\{\beta+\frac{\left(1+\beta^{2}\right)}{(\alpha-\beta)}\right\}+\cot ^{-1}\left\{\gamma+\frac{\left(1+\gamma^{2}\right)}{(\beta-\gamma)}\right\}+\cot ^{-1}\left\{\alpha+\frac{\left(1+\alpha^{2}\right)}{(\gamma-\alpha)}\right\}$ is equal to :
Select the correct option:
A
$\frac{\pi}{2}-(\alpha+\beta+\gamma)$
B
$0$
C
$\pi$
D
$3 \pi$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
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