When vector subtracted from vector |GravitationJEEMain2023.

JEE MAIN 2023

11-4-2023

Question

If V is the gravitational potential due to sphere of uniform density on it’s surface, then it’s value at the center of sphere will be:-

Select the correct option:

$\frac{3 V}{2}$

$\frac{4}{3} v$

$\frac{\mathrm{V}}{2}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Sol. $$ \begin{aligned} & V=\frac{G M}{2 R^3}\left(3 R^2-r^2\right) \text { at } r=R \Rightarrow V=\left(\frac{G M}{R}\right) \\ & \text { at } r=0, V_0=\frac{3 G M}{2 R}=\left(\frac{3 V}{2}\right) \end{aligned} $$

Question Tags

JEE Main

Chemistry

Easy

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