In a high school, a committee has to be formed from a group of 6 boys $\mathrm{M}_1, \mathrm{M}_2, \mathrm{M}_3, \mathrm{M}_4, \mathrm{M}_5, \mathrm{M}_6$ and 5 girls $\mathrm{G}_1, \mathrm{G}_2, \mathrm{G}_3, \mathrm{G}_4, \mathrm{G}_5$.
(i) Let $\alpha_1$ be the total number of ways in which the committee can be formed such that the committee has 5 members, having exactly 3 boys and 2 girls.
(ii) Let $\alpha_2$ be the total number of ways in which the committee can be formed such that the committee has at least 2 members, and having an equal number of boys and girls.
(iii) Let $\alpha_3$ be the total number of ways in which the committee can be formed such that the committee has 5 members, at least 2 of them being girls.
(iv) Let $\alpha_4$ be the total number of ways in which the committee can be formed such that the committee has 4 members, having atleast 2 girls and such that both $\mathrm{M}_1$ and $\mathrm{G}_1$ are NOT in the committee together. The correct option is :