Current Electricity _JEE-Main 09-01-2020_(S2) - Competishun – Live JEE & NEET Courses and Exam Prep

JEE MAIN 2020

09-01-2020 S2

Question

In a meter bridge experiment S is a standard resistance. R is a resistance wire. It is found that balancing length is l = 25 cm. If R is replaced by a wire of half length and half diameter that of R of same material, then the balancing distance l′ (in cm) will now be _______.

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Solution

$\begin{aligned} & \frac{S}{R}=\frac{75}{25}=3 \\ & R^{\prime}=2 R \\ & \frac{S}{2 R}=\frac{3}{2}=\frac{100-I^{\prime}}{I^{\prime}} \\ & I^{\prime}=40 \mathrm{~cm}\end{aligned}$

Question Tags

JEE Main

Physics

Medium

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