In the given circuit, the magnitude of $V_L$ and $V_C$ are twice that of $V_R$. Given that $f =50 \mathrm{~Hz}$, the inductance of the coil is $\frac{1}{\mathrm{~K} \pi} \mathrm{mH}$. The value of K is;
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
V
L
=
V
C
=
2
V
R
X
L
=
X
C
=
2
R
X
L
=
10
Ω
ω
L
=
10
2
π
fL
=
10
L
=
10
2
π
f
=
1
10
π
H
=
1000
10
π
mH
L
=
1
1
100
π
;
K
=
1
100
=
0.01
≈
0
Hello 👋 Welcome to Competishun – India’s most trusted platform for JEE & NEET preparation. Need help with JEE / NEET courses, fees, batches, test series or free study material? Chat with us now 👇
