Consider the following reaction.... | JEE Main

JEE MAIN 2024

09.04.24

Question

Consider the following reaction $\mathrm{MnO}_2+\mathrm{KOH}+\mathrm{O}_2 \rightarrow \mathrm{~A}+\mathrm{H}_2 \mathrm{O}$ Product ' $A$ ' in neutral or acidic medium disproportionate to give products ' $B$ ' and ' $C$ ' along with water. The sum of spin-only magnetic moment values of B and C is BM . (nearest integer) (Given atomic number of Mn is 25 .)

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Solution

Sol. $\mathrm{MnO}_2+\mathrm{KOH}+\mathrm{O}_2 \rightarrow \mathrm{~K}_2 \mathrm{MnO}_4+\mathrm{H}_2 \mathrm{O}$ (A) $$ \begin{aligned} & \mathrm{K}_2 \mathrm{MnO}_4 \xrightarrow{\text { Ncutral/acidic solution }} \mathrm{KMnO}_4+\mathrm{MnO}_2 \\ & \mathrm{Mn}^{+4}:-[\mathrm{Ar}] 3 \mathrm{~d}^3 \\ & \mathrm{n}=3, \mu=\sqrt{3(3+2)}=3.87 \text { B.M. } \end{aligned} $$ Nearest integer is (4)

Question Tags

JEE Main

Chemistry

Medium

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