Titration of oxalic acid |JEE Main 2024

JEE MAINS 2024

09.04.24

Question

Only 2 mL of $\mathrm{KMnO}_4$ solution of unknown molarity is required to reach the end point of a titration of 20 mL of oxalic acid $(2 \mathrm{M})$ in acidic medium. The molarity of $\mathrm{KMnO}_4$ solution should be $\_\_\_\_$ M.

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Solution

eq. $\left(\mathrm{KMnO}_4\right)=$ eq. $\left(\mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4\right)$ $$ \mathrm{M} \times 2 \times 5=2 \times 20 \times 2 $$ $$ \mathrm{M}=8 \mathrm{M} $$

Question Tags

JEE Main

Chemistry

Easy

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