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JEE MAIN 2025
29-01-2025 SHIFT-2
Question
Let $\alpha, \beta(\alpha \neq \beta)$ be the values of $m$, for which the equations $x+y+z=1 ; x+2 y+4 z=m$ and $x+4 y+10 z=m^{2}$ have infinitely many solutions. Then the value of $\displaystyle\sum_{n=1}^{10}\left(n^{\alpha}+n^{\beta}\right)$ is equal to :
Select the correct option:
A
440
B
3080
C
3410
D
560
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Easy
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