Let $ \mathrm{X}=\left({ }^{10} \mathrm{C}_1\right)^2+2\left({ }^{10} \mathrm{C}_2\right)^2+3\left({ }^{10} \mathrm{C}_3\right)^2+\ldots .+10\left({ }^{10} \mathrm{C}_{10}\right)^2, $ where ${ }^{10} \mathrm{C}_{\mathrm{r}}, \mathrm{r} \in\{1,2, \ldots . ., 10\}$ denote binomial coefficients. Then the value of $\frac{1}{1430} \mathrm{X}$ is $\_\_\_\_$ .