Let $f: R \rightarrow R$ be a function defined by $f(x)=\left\{\begin{array}{cc}{[x],} & x \leq 2 \\ 0, & x>2\end{array}\right.$ where $[x]$ is the greatest integer less than 0 equal to $x$. If $I=\int_{-1}^2 \frac{x f\left(x^2\right)}{2+f(x+1)} d x$, then the value of (4I-1) is