Let $f(\mathrm{x})=\left|2 \mathrm{x}^2+5\right| \mathrm{x}|-3|, \mathrm{x} \in \mathrm{R}$. If m and n denote the number of points where $f$ is not continuous and not differentiable respectively, then $\mathrm{m}+\mathrm{n}$ is equal to :
Select the correct option:
A
5
B
2
C
0.0
D
3
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Number of points of discontinuity $=0=\mathrm{m}$ Number of points of non-differentiability $=3=n$
Hello 👋 Welcome to Competishun – India’s most trusted platform for JEE & NEET preparation. Need help with JEE / NEET courses, fees, batches, test series or free study material? Chat with us now 👇