Let the position vectors of the vertices A, B and C of a tetrahedron A, B, C, D be $\widehat {\bf{i}} + 2\hat j + \hat k,\hat i + 3\hat j - 2\hat k$ and $2\widehat {\rm{i}} + \widehat {\rm{j}} - \widehat {\rm{k}}$ respectively. The altitude from the vertex D to the opposite face ABC meets the median line segment through A of the triangle ABC at the point E. If the length of AD is $\frac{{\sqrt {110} }}{3}$ and the volume of the tetrahedron is $\frac{{\sqrt {805} }}{{6\sqrt 2 }}$, then the position vector of E is