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JEE MAIN 2025
24-01-2025 SHIFT-1
Question
One mole of the octahedral complex compound ${\rm{Co}}{\left( {{\rm{N}}{{\rm{H}}_3}} \right)_5}{\rm{C}}{{\rm{l}}_3}$ gives 3 moles of ions on dissolution in water. One mole of the same complex reacts with excess of ${\rm{AgN}}{{\rm{O}}_3}$ solution to yield two moles of ${\rm{AgC}}{{\rm{l}}_{({\rm{s}})}}$. The structure of the complex is:
Select the correct option:
A
$\left[ {{\rm{Co}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_5}{\rm{Cl}}} \right]{\rm{C}}{{\rm{l}}_2}$
B
$\left[ {{\rm{Co}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_4}{\rm{Cl}}} \right] \cdot {\rm{C}}{{\rm{l}}_2} \cdot {\rm{N}}{{\rm{H}}_3}$
C
$\left[ {{\rm{Co}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_4}{\rm{C}}{{\rm{l}}_2}} \right] \cdot {\rm{Cl}} \cdot {\rm{N}}{{\rm{H}}_3}$
D
$\left[ {{\rm{Co}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_3}{\rm{C}}{{\rm{l}}_3}} \right] \cdot 2{\rm{N}}{{\rm{H}}_3}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
$\left[ {{\rm{Co}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_5}{\rm{Cl}}} \right]{\rm{C}}{{\rm{l}}_2} \to \underbrace {{{\left[ {{\rm{Co}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_5}{\rm{Cl}}} \right]}^{2 + }}({\rm{ aq}}{\rm{. }}) + 2{\rm{C}}{{\rm{l}}^ - }({\rm{aq}}.)}_{3{\rm{ ions in water }}}$
$\left[ {{\rm{Co}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_5}{\rm{Cl}}} \right]{\rm{C}}{{\rm{l}}_2}({\rm{ (aq}}{\rm{. }}) + 2{\rm{AgN}}{{\rm{O}}_3}({\rm{ aq}}{\rm{. }}) \to$ $\left[ {{\rm{Co}}{{\left( {{\rm{N}}{{\rm{H}}_3}} \right)}_5}{\rm{Cl}}} \right]{\left( {{\rm{N}}{{\rm{O}}_3}} \right)_2}({\rm{ aq}}{\rm{. }}) + 2{\rm{AgCl}}(\;{\rm{s}})$
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