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JEE MAIN 2023
29-1-2023 S2
Question
Reaction of propanamide with $\mathrm{Br}_2 / \mathrm{KOH}(\mathrm{ag})$ produces:
Select the correct option:
A
Ethylnitrile
B
Propylamine
C
Propanenitrile
D
Ethylamine
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Chemistry
Easy
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