Surface tension of a soap... |JEE Main 2023| Surface Tension

JEE MAIN 2023

29-01-2023 S1

Question

Surface tension of a soap bubble is $2.0 \times 10^{-2} \mathrm{Nm}^{-1}$. Work done to increase the radius of soap bubble from 3.5 cm to 7 cm will be : $\left[\right.$ Take $\left.\pi=\frac{22}{7}\right]$

Select the correct option:

$0.72 \times 10^{-4} \mathrm{~J}$

$5.76 \times 10^{-4} \mathrm{~J}$

$18.48 \times 10^{-4} \mathrm{~J}$

$9.24 \times 10^{-4} \mathrm{~J}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Easy

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