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JEE MAIN 2023
31-01-23 S2
Question
The displacement equations of two interfering waves are given by $y_1=10 \sin \left(\omega t+\frac{\pi}{3}\right) \mathrm{cm}$ and $y_2=5[\sin (\omega t)+\sqrt{3} \cos \omega t] \mathrm{cm}$ respectively. The amplitude of the resultant wave is $\_\_\_\_$ cm .
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Question Tags
JEE Main
Physics
Hard
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