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JEE MAIN 2021
25-02-21 S1
Question
The electric field in a region is given $\vec{E}=\left(\frac{3}{5} E_0 \hat{i}+\frac{4}{5} E_0 \hat{j}\right) \frac{N}{C}$. The ratio of flux of reported field through the rectangular surface of area $0.2 \mathrm{~m}^2$ (parallel to $\mathrm{y}-\mathrm{z}$ plane) to that of the surface of area of $0.3 \mathrm{~m}^2$ (parallel to $\mathrm{x}- z$ plane) is a $b$, where $a=$ $\_\_\_\_$ . Here $\hat{i}, \hat{j}$ and $\hat{k}$ are unit vectors along $x, y$ and $z$ axes respectively]
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Question Tags
JEE Main
Physics
Medium
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