The electric field of a plane Waves.|Electromagnetic Waves

JEE MAIN_2019_

S2_100419

Question

The electric field of a plane electromagnetic wave is given by $$ \overline{\mathrm{E}}=\mathrm{E}_0 \hat{\mathrm{i}} \cos (\mathrm{kz}) \cos (\omega \mathrm{t}) $$ The corresponding magnetic field $\bar{B}$ is then given by i.

Select the correct option:

$\bar{B}=\frac{E_0}{C} \hat{j} \sin (k z) \cos (\omega t)$

$\bar{B}=\frac{E_0}{C} \hat{j} \cos (k z) \sin (\omega t)$

$\vec{B}=\frac{E_0}{C} \hat{j} \sin (k z) \sin (\omega t)$

$\bar{B}=\frac{E_0}{C} \hat{k} \sin (k z) \cos (\omega t)$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Physics

Easy

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